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University Linear Algebra — Span and Linear Independence Worksheet

The two questions every later set asks about a list of vectors: what can you build from it, and is any of it wasted? The span of a set described by equations instead of as a list; deciding whether a given vector lies in a span, and finding the weights when it does; linear independence tested by a homogeneous system, and settled at a glance when the set is too big or contains an obvious culprit; the same questions asked of polynomials, matrices and functions; and the vectors in a list that add nothing to its span. Have a look on this page, then print the free PDF when you want to write on it.

Page 1 of the University Linear Algebra Span and Linear Independence practice worksheet

Practice worksheet — free PDF

6 pages 10 questions Letter size, print-ready

No email, no account, no watermark. Teachers: photocopy it for your classes freely. Worked solutions and 7 harder problems come with the University Linear Algebra bundle.

All 10 questions

Each question targets one named concept from the sheet. Read them here, or print the PDF — it has working space under each one.

  1. Q1The Span of a Set of Vectors

    In 4 let W=span{v1,v2}, where v1=(1,0,2,1) and v2=(0,1,1,3).

    1. Find a system of two linear equations in x1,x2,x3,x4 whose solution set is exactly W.
    2. Use your equations to decide which of (3,1,7,6) and (1,1,1,1) lies in W.
  2. Q2The Span of a Set of Vectors

    In P2, the space of polynomials of degree at most 2 with real coefficients, let W=span{1+x,x+x2}.

    1. Show that every pW satisfies p(1)=0.
    2. Show conversely that every pP2 with p(1)=0 lies in W, by writing such a p explicitly as a linear combination of 1+x and x+x2.
    3. Conclude that W={pP2p(1)=0}, and give one polynomial of P2 that is not in W.
  3. Q3Testing Membership in a Span

    In 4 let u1=(1,1,0,2), u2=(0,1,2,1) and u3=(2,0,3,1).

    1. Decide whether b=(4,3,1,6) lies in span{u1,u2,u3}. If it does, give the weights.
    2. Decide whether e1=(1,0,0,0) lies in the same span.
  4. Q4Testing Membership in a Span

    In P3, the space of polynomials of degree at most 3, let p1=1+x3, p2=xx2 and p3=1+x+x2+x3.

    1. Show that r=3+x+3x2+3x3 is a linear combination of p1,p2,p3, and give the weights.
    2. Show that q=2+x+3x2+5x3 is not.
  5. Q5Linear Independence in n-Space

    Decide whether each set in 4 is linearly independent. For a dependent set, give an explicit dependence relation.

    1. {(1,2,1,0),(0,1,3,1),(1,4,5,2)}
    2. {(1,1,0,2),(0,1,1,1),(2,0,1,3),(1,0,1,0)}
  6. Q6Linear Independence in n-Space

    Decide, without row reducing anything, whether each set is linearly independent, and give the reason in one sentence.

    1. {(1,0,2,1),(0,3,1,1),(2,2,0,5),(1,1,1,1),(4,0,3,2)} in 4
    2. {(3,1,0,2,5),(0,0,0,0,0),(1,4,1,0,2)} in 5
    3. {(2,4,6,0,8),(3,6,9,0,12)} in 5
    4. {(1,0,0,0,5),(0,0,3,0,0)} in 5
  7. Q7Linear Independence of Polynomials, Matrices and Functions

    Decide whether each set is linearly independent. For a dependent set, give an explicit dependence relation.

    1. In P3 (polynomials of degree at most 3): {1+x+x2,x+x2+x3,1x3}.
    2. In M2×2 (real 2×2 matrices): {[1201],[0131],[2110],[1011]}.
  8. Q8Linear Independence of Polynomials, Matrices and Functions

    Here functions are vectors, and a set {f1,,fk} is linearly dependent when there are real numbers c1,,ck, not all zero, with c1f1(x)++ckfk(x)=0 for every real x.

    1. Show that {sin(x+π3),sinx,cosx} is linearly dependent by giving an explicit relation. You may use sin(A+B)=sinAcosB+cosAsinB.
    2. Show that {1,x,ex} is linearly independent, by evaluating a vanishing linear combination at x=0, x=1 and x=2.
  9. Q9Dependence Relations and Redundant Vectors

    In 4 consider the list v1=(1,2,0,1),v2=(2,4,0,2),v3=(0,1,1,1),v4=(1,3,1,0),v5=(0,0,1,1).

    1. Find every vector in the list that is a linear combination of the vectors before it, and write each such combination explicitly.
    2. Name three vectors of the list whose span is span{v1,,v5}, and say why nothing is lost.
  10. Q10Synthesis — drawing on several topics in this unit

    In M2×2, the space of real 2×2 matrices, let A1=[1011],A2=[0110],A3=[1101],W=span{A1,A2,A3}.

    1. Show that {A1,A2,A3} is linearly dependent, and give a dependence relation.
    2. Show that W={[abcd]|d=a,c=a+b}.
    3. Decide whether B=[2352] and I2 lie in W; for any that does, write it as a combination of A1 and A2.

The 7 challenge problems for this topic are a separate, paid sheet and are not reproduced here.

What does this set assume? This set stands on CEGEP Linear Algebra — row reduction and reading the type of solution set from an echelon form are used without comment — and on the previous set, Vector Spaces and Subspaces: linear combinations in n-space, the spaces of polynomials, matrices and functions, and the subspace test. CEGEP met independence in the plane and in space; here it restarts in n-space with n of four or more and in spaces that are not n-space at all. Bases, dimension and coordinates are the next set. For functions, independence is shown by evaluating at chosen points or by an identity; the Wronskian is not used in this course. Scalars are real throughout.

Which course is this for? In the public course calendars of Montreal universities, this material is part of the courses numbered MATH 133, MATH 204, MATH 251, MAST 234, MAT1250 and MAT1260. Each course orders and weights the topics its own way, so check your own outline for what your exam covers. Which sets match your course.

The rest of this unit

The worksheet is the practice, and it is free. Two more printable documents cover the same unit and come with the University Linear Algebra bundle: read the notes first, work this sheet, then sit the test closed-book. See what each one covers.

What the Span and Linear Independence notes cover  About the Span and Linear Independence unit test

How to do every concept on this sheet

This is the part worksheet sites usually leave out. Below is the actual reasoning behind each group of questions — not a full solution set, the decisions that get you to one. Read it before you start, or after you get stuck.

A span, described by equations

The span of a set is every linear combination of its vectors. As a list of combinations it is hard to test against; as the solution set of a few equations it is easy. Q1 asks you to turn the span of two vectors in four coordinates into such a system.

From a span to its equations

Ask when a general vector is a combination, and let the answer be the equations.

  1. 1
    Set up the combination with a general target

    Write c₁v₁ + c₂v₂ = (x₁, x₂, x₃, x₄) as an augmented matrix with the unknown coordinates in the last column.

  2. 2
    Row reduce, carrying the x's along

    The last column becomes expressions in x₁, …, x₄.

  3. 3
    Read the consistency conditions

    Each row whose coefficient part is all zeros must have a zero on the right. Those expressions, set equal to zero, are the equations of the span.

Part (b) is the reward: membership becomes substitution into two equations. Q2 does the same in the quadratic polynomials, in two directions. Part (a) checks that every member of the span has the property; part (b) shows every polynomial with the property is a member, by producing the weights. Together they prove two sets are equal, which is how set equality is always proved.

"Conversely" means a new argument. Showing that the span is inside a set does not show the set is inside the span. In Q2(b), start from an arbitrary polynomial with the property, use the property to eliminate one coefficient, and then find weights in terms of the coefficients that remain.

Testing membership in a span

Q3 and Q4 ask the direct question: is this vector a linear combination of these? That is always a linear system whose unknowns are the weights and whose columns are the given vectors.

b ∈ span{u₁, u₂, u₃} ⇔ [ u₁ u₂ u₃ | b ] is consistent

Consistency is the answer; the weights are the evidence. An echelon form settles the question: a row of zeros with a non-zero entry on the right means no. When the answer is yes, back-substitute for the weights and check them by computing the combination. Q3(b) is the same matrix with a different last column — reduce both at once.

Q4 does the same thing with cubic polynomials. Match coefficients of 1, x, x² and x³ to get four equations in three weights. Part (b) asks you to show a combination is impossible, and the proof is the inconsistent row itself — point to it.

Linear independence in n-space

A set is linearly independent when the only combination giving the zero vector is the one with every weight zero. Q5 tests two sets with that definition: the homogeneous system with the vectors as columns has only the trivial solution exactly when every column has a pivot.

A dependent set needs an explicit relation. Stating "there is a free variable" shows dependence but does not give what the question asks for. Choose a value for the free variable, solve for the others, write the relation out with the actual weights, and check it adds to zero.

Q6 asks you to decide four cases without row reducing, with a one-sentence reason each. The reasons are facts the course proves once and then uses everywhere:

Four shortcuts. More vectors than coordinates forces dependence. Any set containing the zero vector is dependent. A set of two vectors is dependent exactly when one of the pair is a scalar multiple of its partner. And vectors whose non-zero entries sit in positions the others leave empty can be seen to be independent by looking at those positions. Match each part to the fact that settles it, and say which one you used.

Independence of polynomials, matrices and functions

Q7 repeats Q5 in two other spaces. For polynomials, a combination is the zero polynomial when every coefficient is zero, so matching the coefficients of each power of x gives the homogeneous system. For 2 × 2 matrices, each of the four entries gives one equation.

Q8 is about functions, where there are no coordinates to match, and the question states the definition carefully: a relation must hold for every real x. Part (a) proves dependence with an identity — expand the first function with the formula given and look for a combination of the other two. Part (b) proves independence by evaluation.

Evaluation can only prove independence one way. If c₁f₁ + c₂f₂ + c₃f₃ is zero for every x, it is zero at the three points you choose, which gives three equations in the weights. If those force every weight to be zero, the set is independent. If they do not, you have learned nothing — a relation that holds at three points need not hold everywhere.

Redundant vectors in a list

Q9 gives five vectors and asks which are combinations of the ones before them. Row reduce the matrix whose columns are the five vectors, in order: a column without a pivot is a combination of the earlier pivot columns, and the reduced form shows the weights. Part (b) follows: removing a vector that is a combination of the others does not change the span, so the pivot columns alone span the same space.

Use the original vectors, not the reduced columns. Row reduction preserves the dependence relations among columns, but the reduced columns themselves span something different. The three vectors you name in part (b) must come from the original list.

The synthesis question

Q10 puts the set together in the 2 × 2 matrices. Part (a) is Q7(b): a homogeneous system from the entries, then an explicit relation. Part (b) is Q1 and Q2 combined — describe the span by conditions on the entries, and show both inclusions. Part (a) helps here, because the relation shows one of the three matrices is redundant. Part (c) is Q3: test each matrix against the conditions, and for any that passes, find its weights on the two matrices that remain.

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Getting the most out of it

Put the vectors in as columns

Membership, independence and redundancy are all questions about the matrix whose columns are the given vectors. Build it the same way every time, in the order the vectors are listed, and the three questions become three readings of one echelon form.

Know which reading answers which question

Consistency of the augmented system answers membership. A pivot in every column answers independence. The non-pivot columns answer redundancy. Before you reduce, write down which of these you are looking for.

Always check a relation

Any explicit combination you produce — weights for membership, or a dependence relation — can be checked in a few seconds by computing it. Do it every time; it catches most arithmetic slips.

Say which shortcut you used

When a quick fact settles independence, name it in your answer. "Too many vectors" and "contains the zero vector" are complete reasons; "obviously dependent" is not.

Want the solutions, or something more challenging?

The worksheet, the questions above and every explanation on this page stay free permanently. Three more PDFs exist for this topic — the worked answer key, a harder problem set, and the answer key to that. They come with the University Linear Algebra Solutions Bundle, beside the unit notes and the unit test, which is what keeps the rest of the series free.

What else exists for Span and Linear Independence

Three PDFs · 12 pages · all three are in the bundle below.

  • Answer key — 4 pages. All 10 questions worked step by step, including the restrictions and the justifications. Not a list of final answers.
  • Challenge problems — 5 pages, 7 problems. A separate sheet at exam-plus difficulty covering the same 5 concepts. Harder than anything on the free sheet.
  • Challenge answer key — 3 pages. Every challenge problem worked to the same standard, with the checks shown.
  • PDF, letter size, print-ready.
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Common questions

Is this worksheet really free?

Yes — the questions are on this page to read, and the PDF downloads directly, no email and no account. The one paid item is optional: the complete University Linear Algebra Solutions Bundle, which covers every set at this level.

Which university courses is this for?

The course codes listed on this page are taken from the public course calendars of universities that teach linear algebra after CEGEP. Each course orders and weights the topics its own way — some treat span and independence in n-space first and abstract spaces later, others do both at once — so check the outline for your own section to see where this set falls in your term.

What do I need to know before starting this set?

CEGEP Linear Algebra, especially row reduction and reading an echelon form, and the previous set, Vector Spaces and Subspaces: linear combinations, the spaces of polynomials and matrices, and the subspace test.

Is a span always a subspace?

Yes. It contains the zero vector (take every weight zero) and is closed under addition and scalar multiplication, because a sum or multiple of linear combinations is another linear combination of the same vectors. It is the smallest subspace containing the given vectors.

What is the difference between spanning and being independent?

Spanning is about having enough vectors to build everything in a space; independence is about having no wasted vectors. A set can do either without the other. A set that does both is a basis, which is the next set.

How do I show functions are linearly independent without the Wronskian?

Assume a combination is zero for every x, evaluate it at a few well-chosen points to get equations in the weights, and show those equations force every weight to be zero. That is the method this set uses; the Wronskian belongs to a differential equations course.

Why doesn't row reducing change which vectors are redundant?

Row operations change the vectors, but not the relations among the columns: a combination of columns is zero before reduction exactly when the same combination is zero after. So the pivot positions of the reduced matrix tell you which original vectors to keep.

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