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University Introductory Statistics — Continuous Distributions and the Normal Model Worksheet

The jump from a list of probabilities to a curve. A density function and the areas under it; the mean and the standard deviation of a continuous variable, found from symmetry or from a supplied formula; the uniform and exponential distributions; standardizing with z and reading a table that only gives one side; percentiles, read by running the table backwards; and the normal approximation to the binomial with its size condition and its continuity correction. Have a look on this page, then print the free PDF when you want to write on it.

Page 1 of the University Introductory Statistics Continuous Distributions and the Normal Model practice worksheet

Practice worksheet — free PDF

7 pages 10 questions Letter size, print-ready

No email, no account, no watermark. Teachers: photocopy it for your classes freely. Worked solutions and 7 harder problems come with the University Introductory Statistics bundle.

8 of the 10 questions

Each question targets one named concept from the sheet. Read them here, or print the PDF — it has working space under each one. 8 of the 10 questions are printed below. The other 2 are built on a diagram or a table of values that does not translate to the page, so they are in the free PDF — marked below where they would have come.

  1. Q1Density Functions and Probability as Area

    This question is built around a diagram or a table of values. Open it in the PDF.

  2. Q2Mean and Variance of a Continuous Random Variable

    The time X, in minutes, that a barista takes to prepare an order has a triangular density: it rises in a straight line from 0 at x=2 to a peak at x=5, then falls in a straight line to 0 at x=8, and is 0 outside [2,8].

    1. Find the height of the peak.
    2. Find E[X], and justify your answer without any formula.
    3. For a triangular density on [a,b] with its peak at c, Var(X)=a2+b2+c2abacbc18. Find Var(X) and SD(X).
    4. Find P(X>7).
  3. Q3The Uniform and Exponential Distributions
    1. A ferry leaves every 20 minutes, and a passenger who ignores the timetable arrives at a random moment, so the wait W, in minutes, is uniform on [0,20]. Find P(W>15) and P(5<W<12).
    2. For a uniform variable on [a,b], E[W]=a+b2 and Var(W)=(ba)212. Find the mean and standard deviation of the wait.
    3. At a bike-share dock, the time T, in minutes, between two returns is exponential with mean 4 minutes, so P(Tt)=1et/4 for t0. Find P(T>8) and P(2<T6), exactly and to four decimals. Use e0.5=0.6065, e1.5=0.2231, e2=0.1353.
  4. Q4The Standard Normal Table and Standardizing

    Let Z be a standard normal variable. The table available gives P(Z<z) for z0 only: P(Z<0.62)=0.7324,P(Z<0.84)=0.7995,P(Z<1.37)=0.9147,P(Z<1.50)=0.9332. Find:

    1. P(Z<1.37);
    2. P(Z>0.84);
    3. P(1.50<Z<0.62);
    4. P(|Z|>1.37).
  5. Q5The Standard Normal Table and Standardizing

    This question is built around a diagram or a table of values. Open it in the PDF.

  6. Q6Percentiles of a Normal Distribution

    We write N(μ,σ2) with the variance second. The battery life X, in hours, of a tablet is N(11,2.25). Use whichever of these you need: P(Z<1.2816)=0.9000,P(Z<1.6449)=0.9500,P(Z<1.9600)=0.9750.

    1. Find the 90th percentile of battery life.
    2. Find the battery life that only 5% of tablets fall short of.
    3. Find the interval, symmetric about the mean, that contains the middle 80% of battery lives.
  7. Q7Percentiles of a Normal Distribution

    We write N(μ,σ2) with the variance second. A courier's delivery time T, in hours, is N(μ,16), and the courier can shift μ by changing its routing. Use whichever of these you need: P(Z<2.0537)=0.9800,P(Z<2.3263)=0.9900.

    1. Find the largest mean μ for which only 1% of deliveries take longer than 48 hours.
    2. Suppose instead the mean is fixed at 40 hours and the courier works on reliability. What standard deviation would give the same guarantee, P(T>48)=0.01?
  8. Q8The Normal Approximation to the Binomial

    A survey firm places 150 calls, and each call is answered independently with probability 0.40. Let X be the number answered. Take the normal approximation to be acceptable when np10 and n(1p)10. Use P(Z<0.75)=0.7734 and P(Z<1.75)=0.9599.

    1. Find the mean and standard deviation of X, and check that the normal approximation is acceptable.
    2. Using the continuity correction, approximate P(X71).
    3. Using the continuity correction, approximate P(56X64).
  9. Q9The Normal Approximation to the Binomial
    1. Take the normal approximation to Bin(n,p) to be acceptable when np10 and n(1p)10. For each of the following, decide whether it is acceptable: Bin(40,0.1); Bin(400,0.03); Bin(60,0.95).
    2. X is binomial and Y is the normal variable approximating it. Rewrite each event about X as an event about Y, using the continuity correction: X<30;\; X30;\; X=30;\; X>30;\; 25X<30.
  10. Q10Synthesis — drawing on several topics in this unit

    We write N(μ,σ2) with the variance second. The volume of paint in a tin labelled 1 litre is N(1000,64) millilitres, and a tin is underfilled if it holds less than 988~mL. Tins are filled independently. Take the normal approximation to the binomial to be acceptable when np10 and n(1p)10. Use whichever of these you need: P(Z<1.09)=0.8621, P(Z<1.18)=0.8810, P(Z<1.50)=0.9332.

    1. Find the probability p that a tin is underfilled.
    2. A shipment holds 500 tins. Using the continuity correction, approximate the probability that 40 or more of them are underfilled.

The 7 challenge problems for this topic are a separate, paid sheet and are not reproduced here.

What does this set assume? This set assumes Secondary 5 mathematics only — areas of rectangles, triangles and trapezoids, the algebra needed to solve one equation for one unknown, and comfort with decimals. It is not calculus-based, and no question anywhere in this course asks for a derivative or an integral: every area here is found by geometry or read from a distribution function that the question supplies. From Discrete Random Variables it takes expectation, variance and standard deviation as ideas, and the binomial distribution with its mean and standard deviation, which the last two sheets approximate. From Probability Rules and Conditional Probability it takes complements and the probability of an interval; from Descriptive Statistics, the shape of a distribution and the meaning of a standard deviation. What stays out is deliberate: no integration of a density, no moment generating functions, no joint, marginal or conditional densities, no gamma or beta distributions, no software output and no named calculator routine — a printed table and a non-programmable calculator are all that is assumed. Sampling distributions, the standard error of a sample mean and the central limit theorem come next, in Sampling Distributions and the Central Limit Theorem.

Which course is this for? In the public course calendars of Montreal universities, this material is part of the courses numbered MAST 333, MAST 221, STAT 249, STT1700, MAT1720, MAT1185, MATH 10603 and MAT350. Each course orders and weights the topics its own way, so check your own outline for what your exam covers. Which sets match your course.

How to do every concept on this sheet

This is the part worksheet sites usually leave out. Below is the actual reasoning behind each group of questions — not a full solution set, the decisions that get you to one. Read it before you start, or after you get stuck.

Density functions and probability as area

A discrete variable carries a probability at each value; a continuous one carries probability over intervals, as area under a curve. Two properties do all the work: the density is never negative, and the total area under it is 1. Q1 gives a triangular density as a graph with its peak height h unnamed, so the first part is the total-area property turned into an equation for h.

Reading a probability off a piecewise-linear density

Geometry, not calculus.

  1. 1
    Sketch and shade

    Draw the region the event describes on the graph before computing anything: to the left of a value, to the right, or between two values.

  2. 2
    Cut it into shapes you know

    A triangle, a rectangle, a trapezoid, or a big shape with a corner removed. Find the height of the slanted edge at the cut by similar triangles or by the equation of the line.

  3. 3
    Add the pieces, and sanity-check against 1

    Every area must land between 0 and 1, and complementary regions must add to 1.

That is Q1(b) and Q1(c). The cut in Q1(b) falls on the rising edge in one part and on the falling edge in the other, so the two are not mirror images and each needs its own height. Q1(c) can be done directly or as 1 minus the two outer pieces you already have — do it both ways once, and the agreement is the check.

A single value is not an interval. Q1(d) asks for P(X = 2) and then for one sentence of explanation. Answer it from what a probability is for a continuous variable — the area of a region — and ask what width that region has. The sentence is the part that earns the mark, and it is also why ≤ and < may be swapped freely here but never for a discrete variable.

The mean and the spread of a continuous variable

Q2 is the same kind of density with a different demand: locate its centre and measure its spread. Part (a) is the total-area property again. Part (b) forbids any formula, so the justification has to come from the picture.

The mean is the balance point. Think of the region under the density as a flat plate: E(X) is where it balances on a knife edge. So check first whether the density is symmetric about some vertical line. If it is, that line is the balance point and one sentence settles part (b); if it is not, the mean is pulled towards the longer tail and a formula is needed. Deciding which case you are in is the whole of the question.

Q2(c) hands you the variance formula for a triangular density, so use it exactly as printed — substitute the two endpoints and the peak, and do not try to rebuild it. The standard deviation is the square root of what comes out, in the same units as X, which is why it is the number worth interpreting. Q2(d) returns to area, on the falling edge only.

Check the standard deviation against the picture. For a density that lives on an interval, a standard deviation larger than about a quarter of that interval's length, or smaller than a twentieth of it, is nearly always an arithmetic slip. Substituting into a supplied formula is where sign and bracket errors hide.

The uniform and exponential distributions

Two named non-normal models, both handled without calculus. The uniform density on an interval is a flat line, so every probability is the area of a rectangle: the width of the event divided by the width of the whole interval.

W uniform on [a, b]: P(c < W < d) = (d − c)/(b − a)

Q3(a) is that ratio twice, and the second event is an interval strictly inside the range rather than a tail. Q3(b) supplies the mean and the variance of a uniform variable, so the only decisions left are substituting the endpoints the question names and remembering that the standard deviation asked for is the square root of the variance, not the variance itself.

An exponential question gives you its distribution function. Q3(c) states P(T ≤ t) for the waiting time, so every probability is one subtraction or two. A "more than" event is 1 minus the function at that point; an event between two times is the function at the later time minus the function at the earlier one. Substitute, then use the three exponential values printed in the question rather than reaching for a calculator key — the question asks for an exact expression as well as a rounded one, so keep the exact form on the line above.

The standard normal table and standardizing

Z is the normal variable with mean 0 and standard deviation 1, and the table in Q4 gives P(Z < z) for z ≥ 0 only. That restriction is the point of the question: every other kind of event has to be rewritten as one or more of those left-tail readings.

P(Z > z) = 1 − P(Z < z), P(Z < −z) = 1 − P(Z < z), P(a < Z < b) = P(Z < b) − P(Z < a)

Turning an event into table readings

Sketch first, every time.

  1. 1
    Draw the bell and shade the event

    Mark 0 and the z values. The picture decides whether you are adding, subtracting or doubling.

  2. 2
    Use symmetry to move to the right half

    The curve is symmetric about 0, so the area left of a negative value equals the area right of its positive twin.

  3. 3
    Write the answer as a combination of P(Z < z) values

    Only then look anything up. Q4(d) is an absolute value, which is two tails at once — say in words what |Z| > z means before touching the table.

Q5 moves to a variable that is not standard, and its first trap is notation: N(μ, σ²) puts the variance second, so take a square root before doing anything else. The question says so explicitly, and the same warning is repeated in Q6, Q7 and Q10 because it costs more marks than any other single slip in this chapter.

z = (x − μ)/σ, so P(X < x) = P(Z < z)

Q5(a) is one standardization; Q5(b) is two, with a subtraction between them, and it also asks you to shade the region on the printed curve — do that before computing, since a shaded picture that disagrees with your arithmetic catches a reversed subtraction immediately. Q5(c) uses the 68–95–99.7 rule instead of the table: count how many standard deviations each endpoint sits from the mean, and if the count is a whole number the rule applies directly. The tick marks on the printed curve are placed at exactly those distances, so the counting is done by looking.

Percentiles: running the table backwards

Everything so far went from a value to a probability. Q6 and Q7 go the other way: the probability is given and something else is unknown. The move is always the same — write the standardized statement, match the given area to a z from the printed list, then solve.

x = μ + zσ

Q6(a) asks for the value with a stated area below it. Q6(b) is worded as a shortfall rather than as a percentile, so the first job is translating "only 5% fall short of it" into an area on the correct side, which puts z below zero and calls for the symmetry step of Q4. Q6(c) is an interval symmetric about the mean holding a stated middle share: split what is left over into two equal tails, find the z that cuts off one of them, and build both endpoints with ± in one line.

Match the area to the table before you pick a sign. The printed values are all for areas above one half, so a percentile below the mean uses the same z with a minus sign. Sketching the bell and shading the stated area is what fixes the sign; reading the list from the top is what loses it.

Q7 keeps the probability fixed and makes a parameter the unknown. In part (a) the mean is unknown and the standard deviation is given; in part (b) the mean is fixed and the standard deviation is unknown, with the same guarantee to be met. Both parts start identically: convert the stated tail probability into the z that cuts it off, write z = (x − μ)/σ with the one unknown left in place, and solve the resulting linear equation. Part (b) is worth a sentence afterwards — the two parts are two different ways of buying the same guarantee, and saying which lever each one pulls is the interpretation the question is after.

The normal approximation to the binomial

A binomial count with a large n is tedious to compute exactly, and its histogram looks like a bell. The approximation replaces X by a normal variable with the binomial's own mean and standard deviation — but only when the distribution is not badly lopsided, which is what the size condition tests.

μ = np, σ = √(np(1 − p)), usable when np ≥ 10 and n(1 − p) ≥ 10

Q8(a) asks for both numbers and for the condition to be checked in writing, with both quantities evaluated — an approximation used without its check is incomplete even when it is justified. Q8(b) and Q8(c) then apply it to a one-sided and a two-sided event.

Why the half-unit appears. X takes whole-number values; the normal curve is spread continuously. Each whole number is represented by the strip reaching half a unit either side of it, so an event about X becomes an event about the union of those strips, and the boundary of the event moves by half a unit. Which way it moves depends on whether the endpoint is included in the event or excluded from it — decide that from the wording, in words, before writing any number down.

Q9 strips both ideas down to their mechanics. Q9(a) is three size checks and nothing else: write out both products for each one and compare each against the threshold. The three pairs (n, p) are chosen to be unalike — one has a small n, one a p near 0, one a p near 1 — and which of the two products is the binding one changes with them, so never check only np. Q9(b) is five events about X to be rewritten as events about the approximating normal variable. Take them one at a time and say each in words first ("fewer than 30", "30 or fewer"); the one stated as an equality needs the same reasoning as the inequalities, not a shortcut.

Strict and non-strict inequalities differ here. For a continuous variable the two are interchangeable, as Q1(d) shows. For a binomial count they are not, and the continuity correction is exactly where that difference has to be honoured. Q9(b) puts X < 30 and X ≤ 30 side by side for that reason.

The synthesis question

Q10 chains the chapter together. Part (a) is a normal probability of the Q5 kind, with the variance given second once more. Part (b) then treats that probability as the p of a binomial count over a shipment, checks the size condition on it, and approximates a one-sided event with the continuity correction — so an error in part (a) propagates, and it is worth confirming that the probability from part (a) is plausible from the picture before building on it. The chain is the lesson: a proportion produced by a continuous model becomes the parameter of a discrete count, which is then approximated by a continuous model again.

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Getting the most out of it

Sketch the curve before every calculation

A bell with the mean marked and the event shaded, or a triangle with the region cut into shapes: the picture decides whether you subtract, add or double, and it catches a tail taken on the wrong side faster than any re-reading of the arithmetic.

Say out loud which number the second slot holds

N(μ, σ²) is written with the variance second throughout this set. Before standardizing, write σ on its own line as the square root of that number. More marks are lost to this one habit than to the table itself.

Ask which direction the question runs

Value to probability, or probability to value? The first standardizes and looks up; the second matches an area to a z and solves for what is missing. Naming the direction first tells you which of the two templates to write down.

Check whether the variable is a count

If it counts whole things, it is discrete: the size condition has to be checked before a normal curve may be used, and the boundaries need the half-unit shift. If it measures something on a continuous scale, neither applies.

Finish with a sentence

Every number here describes something — a wait, a mass, a battery life, a count of calls. Write what it means in the context, in words, next to the number. Several parts of this set award marks for that sentence alone.

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The worksheet, the questions above and every explanation on this page stay free permanently. Three more PDFs exist for this topic — the worked answer key, a harder problem set, and the answer key to that. They come with the University Introductory Statistics Solutions Bundle, beside the unit notes and the unit test, which is what keeps the rest of the series free.

What else exists for Continuous Distributions and the Normal Model

Three PDFs · 12 pages · all three are in the bundle below.

  • Answer key — 2 pages. All 10 questions worked step by step, including the restrictions and the justifications. Not a list of final answers.
  • Challenge problems — 7 pages, 7 problems. A separate sheet at exam-plus difficulty covering the same 6 concepts. Harder than anything on the free sheet.
  • Challenge answer key — 3 pages. Every challenge problem worked to the same standard, with the checks shown.
  • PDF, letter size, print-ready.
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Common questions

Is this worksheet really free?

Yes — the questions are on this page to read, and the PDF downloads directly, no email and no account. The one paid item is optional: the complete University Introductory Statistics Solutions Bundle, which covers every set at this level.

Which university courses is this for?

The course codes listed on this page are taken from the public course calendars of universities that teach a first, service-level statistics course. Each course orders and weights the chapters its own way, and some reach a chapter later or not at all — so check the outline for your own section to see where this set falls in your term.

Do I need calculus for this set?

No. Every area is found with the geometry of a triangle, a rectangle or a trapezoid, or read from a distribution function printed in the question, and no part asks for a derivative or an integral. Secondary 5 mathematics is enough.

What do I need to know before starting this set?

Expectation, variance and standard deviation as ideas, and the binomial distribution with its mean and standard deviation, from Discrete Random Variables. Areas of simple shapes and solving a linear equation for one unknown cover the rest.

Does N(μ, σ²) hold the variance or the standard deviation?

The variance. Every question in this set states it explicitly, and the second number has to be square-rooted before it is used in z = (x − μ)/σ. Some courses write the standard deviation second instead, so check the convention your own section uses.

Why can P(X = 2) behave differently for a continuous variable?

Because a probability is an area, and an area needs a width. That is also why a strict and a non-strict inequality can be swapped for a continuous variable but not for a count — which is exactly what the continuity correction exists to handle.

The table gives only the left tail for positive z. How do I read a negative one?

By symmetry. The curve is a mirror image about 0, so the area to the left of a negative value equals the area to the right of its positive twin, and the area to the right of any value is 1 minus the area to its left. Two identities cover every case on the sheet.

When may I use the normal approximation to the binomial?

When both np and n(1 − p) reach 10 — the threshold this set uses, and the one stated in every question that needs it. Show both products; a course that uses a different threshold, such as 5, changes only that comparison and nothing else in the method.

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