University Introductory Statistics — Discrete Random Variables Worksheet
The chapter where a probability model becomes a number you can average. Probability mass functions and the cumulative distribution function F(x) = P(X ≤ x); expected value as a long-run average and as a balance point; variance from the definition and from the shortcut, and what a linear transformation does to both; Bernoulli trials, the binomial formula and the four conditions a situation has to meet before the formula is allowed; the cumulative binomial table and the mean and variance that come with the model; and the Poisson distribution for counts over an interval — in settings from road tests to bike-share repairs to a help line. Have a look on this page, then print the free PDF when you want to write on it.
Practice worksheet — free PDF
No email, no account, no watermark. Teachers: photocopy it for your classes freely. Worked solutions and 7 harder problems come with the University Introductory Statistics bundle.
7 of the 11 questions
Each question targets one named concept from the sheet. Read them here, or print the PDF — it has working space under each one. 7 of the 11 questions are printed below. The other 4 are built on a diagram or a table of values that does not translate to the page, so they are in the free PDF — marked below where they would have come.
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Q1Probability Mass Functions and Cumulative Distributions
A driving school records , the number of attempts a student needs to pass the road test. Its instructors model the distribution by and for every other .
- Find the constant and write the probability mass function as a table.
- Write the cumulative distribution function for every real number .
- Use to find , and .
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Q2Expected Value of a Discrete Random Variable
This question is built around a diagram or a table of values. Open it in the PDF.
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Q3Expected Value of a Discrete Random Variable
This question is built around a diagram or a table of values. Open it in the PDF.
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Q4Variance and Linear Transformations of a Random Variable
This question is built around a diagram or a table of values. Open it in the PDF.
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Q5Variance and Linear Transformations of a Random Variable
A ski-rental shop rents snowboards in a weekday hour, where and . Each rental brings in $25, and the hour's staffing costs $40, so the hour's net revenue is dollars.
- Find , and .
- Find the mean and the standard deviation of .
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Q6Bernoulli Trials and the Binomial Formula
For each situation, decide whether has a binomial distribution, exactly or to a good approximation (say which). If it does, give and ; if it does not, name a condition of the binomial model that fails.
- A student guesses at random on all questions of a quiz, each with options of which one is correct; is the number of correct answers.
- From a box of phone chargers, of them faulty, a technician takes without replacement; is the number of faulty chargers taken.
- A player rolls a fair die until a six appears; is the number of rolls.
- In a city of million adults, cycle to work. A survey chooses adults at random; is the number of them who cycle to work.
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Q7Bernoulli Trials and the Binomial Formula
A gardener plants seeds of a variety for which each seed, independently, fails to germinate with probability . Let be the number of seeds that fail. You may use , and .
- Find .
- Find the probability that at most one seed fails.
- Find the probability that at least two seeds fail.
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Q8Binomial Tables, Mean and Variance
This question is built around a diagram or a table of values. Open it in the PDF.
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Q9Binomial Tables, Mean and Variance
- A courier knows that of its parcels, independently, need a second delivery attempt. For a driver's round of parcels, let be the number needing a second attempt. Find , and .
- A binomial variable has mean and variance . Find its and .
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Q10The Poisson Distribution
Calls reach a small software firm's help line at an average rate of per hour, and the number of calls in an hour is modelled as , so that for You may use and .
- Find and .
- State the mean and the standard deviation of .
- Find the probability that no call arrives during a -minute coffee break, and the probability that at least one does.
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Q11Synthesis — drawing on several topics in this unit
An airport shuttle van has passenger seats. Because some passengers do not turn up, the company accepts bookings for each trip. Each booked passenger turns up with probability , independently of the others. Let be the number who turn up. You may use and .
- Name the distribution of , with its parameters, and find and .
- Find the probability that the van is overbooked (a passenger who turns up has no seat).
- Find the probability that the van leaves with at least one empty seat.
- Let be the number of passengers left without a seat. Write the distribution of and find .
The 7 challenge problems for this topic are a separate, paid sheet and are not reproduced here.
What does this set assume? This set assumes Secondary 5 mathematics only — fractions and decimals handled comfortably, summation notation, solving a small pair of simultaneous equations, and powers on a calculator. It is not calculus-based: no question here asks for a derivative or an integral. It leans on two earlier University Introductory Statistics sets — Descriptive Statistics, for the idea of a mean and a standard deviation as centre and spread, and Probability Rules and Conditional Probability, for independence, the multiplication rule and the combinations C(n, r) that the binomial formula counts with. What comes after it is deliberately not here: densities and probability as area, the normal model and the normal approximation to the binomial all belong to the next set, Continuous Distributions and the Normal Model, and anything about a sample mean belongs to Sampling Distributions and the Central Limit Theorem. The binomial and the Poisson are the only named discrete models in this course; the geometric, hypergeometric, negative binomial and multinomial distributions are out, as are moment generating functions, joint and conditional distributions, covariance and Chebyshev's theorem. No question uses software or a spreadsheet: the tools are a non-programmable calculator and a printed table.
Which course is this for? In the public course calendars of Montreal universities, this material is part of the courses numbered MAST 221, STAT 249, STT1700, MAT1720, MAT1185, MATH 10603 and MAT350. Each course orders and weights the topics its own way, so check your own outline for what your exam covers. Which sets match your course.
How to do every concept on this sheet
This is the part worksheet sites usually leave out. Below is the actual reasoning behind each group of questions — not a full solution set, the decisions that get you to one. Read it before you start, or after you get stuck.
Probability mass functions and cumulative distributions
A discrete random variable is a rule that attaches a number to each outcome. Its probability mass function lists the values it can take and the probability of each, and it is a legitimate model only when every probability is between 0 and 1 and the whole list adds to 1. That second condition is not decoration — it is the equation that pins down an unknown constant.
Σ P(X = x) = 1, over every value x the variable can takeQ1 gives a formula with an unknown multiplier in it and a short list of allowed values. Write the four probabilities in terms of the constant, add them, set the sum equal to 1, and solve the one-line equation; only then is the table worth writing out. Finishing with a table rather than the formula is part of the question, and it is also the fastest way to check your own constant — four numbers that do not add to 1 are visible at a glance.
F is defined for every real number, not just the values of X. Q1(b) says every real number and means it. Between two values of X nothing new becomes possible, so F stays flat; at each value it jumps by exactly that value's probability; below the smallest value it is 0 and from the largest value onward it is 1. Write it as a piecewise function with an interval for each flat stretch, not as a row of four numbers.
Q1(c) then asks for three probabilities read off F rather than off the table, which is the skill the sheet is really after. Translate each one into F before touching a number:
P(X ≤ a) = F(a), P(a < X ≤ b) = F(b) − F(a), P(X ≥ a) = 1 − P(X < a)The strictness of an inequality matters here in a way it never does for a continuous model. P(X < a) and P(X ≤ a) differ by the whole jump at a, so a question written with < is not the same question as one written with ≤. When the point asked about is not one of the values of X, it sits on a flat stretch and F takes the value it already had.
Expected value of a discrete random variable
The expected value is the average of the values, weighted by their probabilities — the balance point of the mass function, not necessarily a value the variable can ever take.
E[X] = μ = Σ x · P(X = x)Q2 runs that definition backwards. Two probabilities in the table are unknown and two facts are given: the probabilities add to 1, and the mean is stated. Write each fact as an equation in the two unknowns and solve the pair; a negative probability or one above 1 at the end means an arithmetic slip, not an unusual answer. Q2(b) then asks for a probability described in words — more scoops than the mean. Decide first which values of X satisfy the description, strictly, and add only their probabilities.
A cost is a function of X, and its mean is not the cost of the mean. Q3(b) asks for the expected daily repair cost, where the charge is nothing when no bicycle is out of service and a call-out fee plus a per-bicycle amount when at least one is. That rule is not linear — it jumps at zero — so substituting E[X] into it gives the wrong number. Use the definition for a function of X instead.
In practice that means one extra column beside the table: for each value of X work out what the cost would be, then weight those costs by the same probabilities. Q3(a) is the plain mean of X and is worth doing first, because it is one of the columns you need anyway.
Variance, standard deviation and the shortcut
Variance is the expected squared distance from the mean, and the standard deviation is its square root, back in the units of X.
Var(X) = σ² = E[(X − μ)²] = E[X²] − μ², SD(X) = σ = √Var(X)Q4 asks for both routes on the same table, on purpose. The definition needs a column of (x − μ)² and is the version that makes the meaning visible; the shortcut needs a column of x² and is the version you will use under time pressure. They are algebraically the same quantity, so two different answers mean an error in one column, and finding which one is the point of doing it twice.
Three things a variance can never be. Negative — every term of the definition is a square times a probability. Larger than the largest squared distance from the mean. In the units of X — those belong to the standard deviation. Check all three before moving on; each catches a different slip.
Linear transformations of a random variable
Shifting a variable moves its centre and leaves its spread alone; scaling it moves both, and the variance moves by the square of the scale factor.
E[aX + b] = a E[X] + b, Var(aX + b) = a² Var(X), SD(aX + b) = |a| · SD(X)Q5 supplies a mean and a standard deviation and never a table, which is the signal that these three rules are the whole method — there is nothing to sum. In Q5(a) the net revenue is a fixed amount per rental minus a fixed hourly staffing cost, so read a and b off the expression and apply each rule in turn. The constant b is the trap: it moves the mean and does nothing at all to the variance or the standard deviation.
Standardizing is a linear transformation in disguise. Q5(b) subtracts a constant and divides by another, which looks like a new kind of question and is not. Rewrite it in the form aX + b first — the divisor becomes a multiplier of one over that number — then apply exactly the same two rules. Squaring a fractional a is where marks are lost.
Bernoulli trials and the binomial formula
The binomial model counts successes in a fixed number of independent trials that all have the same success probability. All four of those conditions have to hold before the formula means anything.
The four conditions
Check them in this order, on the wording of the question.
- 1A fixed number of trials, n
Decided before you start. A rule that says "keep going until something happens" does not fix n, so the count of trials is not a binomial variable.
- 2Two outcomes per trial
Every trial ends in the event you are counting or its complement, with nothing in between.
- 3The same p on every trial
Drawing without replacement changes p as the pool shrinks; drawing with replacement, or from a population enormous compared with n, keeps it effectively constant.
- 4Independent trials
What happened on one trial tells you nothing about the next. This is the condition that "without replacement" breaks along with condition 3.
Q6 is four situations and no arithmetic whatsoever. For each one the answer has a fixed shape: either the four conditions hold — exactly, or well enough to be a good approximation, and the question asks you to say which — and then you state n and p; or one condition fails, and you name it. Work through the list above in order rather than deciding by feel, and say where each number comes from: n is what the situation repeats, p is the probability of the thing being counted on a single trial.
Name X before you name the distribution. Counting failures and counting successes are different variables with different values of p on the same situation. Q7 counts seeds that fail, so p is the probability of failing and the formula is applied to that variable throughout — not to its complement halfway through.
Q7 gives you three powers to save arithmetic, which is a hint about the shape of the work: the parts that are quick are the ones built from a small number of terms. Q7(b) is a sum of two terms straight from the formula. Q7(c) describes an event whose complement is exactly the event in Q7(b), and subtracting from 1 is much shorter than adding five terms — the general move whenever a question says "at least".
Binomial tables, mean and variance
A printed cumulative table gives P(X ≤ k) and nothing else, so every question has to be rewritten in that form before you look anything up. Q8 is five rewritings and five lookups.
P(X = k) = F(k) − F(k − 1), P(X > k) = 1 − F(k), P(a ≤ X ≤ b) = F(b) − F(a − 1), P(X < k) = F(k − 1)Off by one is the whole difficulty. Because X takes whole-number values, "more than k" is "at least k + 1" and "fewer than k" is "at most k − 1". Write the rewriting down as a line of algebra before you read the table; a lookup made straight from the words is the single most common lost mark on this sheet.
The mean and variance of a binomial variable need no table and no sum, because the model already fixes them:
E[X] = np, Var(X) = np(1 − p), SD(X) = √(np(1 − p))Q9(a) applies those three to a stated n and p. Q9(b) runs them backwards: two equations, two unknowns, and the quickest route is to divide the variance by the mean, because everything but one factor cancels and p follows from what is left. Then recover n from the mean. Finish by checking that p lies between 0 and 1 and that n is a whole number — if either fails, no binomial variable has those two moments.
The Poisson distribution
The Poisson model counts events in a fixed interval of time or space when they occur at a constant average rate, independently of one another, and there is no natural n to count out of. One parameter does all the work.
P(X = x) = e⁻ᵐ mˣ / x!, E[X] = m, Var(X) = m, SD(X) = √mQ10 states the rate per hour and supplies the exponential values you need, so the arithmetic is short and the decisions are everything. Q10(a) is one term of the formula and then a sum of the terms up to a stated value. Q10(b) is a statement, not a computation: the mean and the variance of a Poisson variable are the same number, which is why the standard deviation is a square root of it — say so rather than adding a column.
Rescale the rate, never the probability. Q10(c) asks about a period shorter than the one the rate was quoted for. Multiply the rate by the fraction of the original interval, and use that new parameter in the same formula. A probability for an hour cannot be scaled down to a probability for twenty minutes. The second half of Q10(c) is an "at least one", so its complement is the single term you have just computed.
The synthesis question
Q11 is the overbooking problem, and it uses most of the sheet at once. Q11(a) asks you to name the distribution with its parameters before anything else: run the four conditions over the wording, read n and p off it, and then the mean and standard deviation are the binomial formulas rather than a table of eleven rows. The two probabilities printed in the question are there because the parts that follow need exactly those and no others — a sign that each part should reduce to a short combination of them.
Q11(b) and (c) are both translations before they are computations. Say in plain words which values of X describe an overbooked van, and which describe a van leaving with a seat free; the two descriptions between them should account for every possible value, which is the check. Then rewrite each as a cumulative or complementary probability, exactly as in Q8.
A count of people left behind is its own random variable. In Q11(d), B is not X and is not binomial: it takes only a few values, and several values of X give the same value of B. Build its mass function by asking, for each value B can take, which values of X produce it and adding those probabilities — then E[B] is the ordinary weighted sum, and it is perfectly normal for it to be a small fraction of a person.
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Getting the most out of it
Draw the table, even when you are given a formula
Values across the top, probabilities beneath, then one extra row for whatever the question needs — x·P(x), x², (x − μ)², a cost. Almost every question in this set is one more row on a table you have already written, and a table that does not add to 1 stops you before the error spreads into the mean.
Translate the words before you compute
"At least", "more than", "fewer than", "at most", "more than the mean": write each as an inequality on X, then as an expression in F or in the mass function, and only then reach for the calculator. On a whole-number variable, moving between < and ≤ changes the answer, and it is where this chapter's marks are lost.
Name the model before using its formulas
np, np(1 − p) and the single Poisson parameter are shortcuts that are only valid once the model is justified. Write the conditions you checked, in one line, above the formula. An exam question that says "find the probability" is also silently asking you to defend the model you chose.
Reach for the complement
"At least one", "more than five", "not all": write the complement beside the event and count the terms each version needs. The complement usually wins, and with a cumulative table it is one subtraction rather than a column of additions.
Sanity-check every answer against the table
A probability outside 0 to 1, a mean outside the range of values, a standard deviation larger than that range, a variance carrying the units of X: each is a thirty-second check and each catches a different mistake. Do them before writing the sentence that interprets the result.
Want the solutions, or something more challenging?
The worksheet, the questions above and every explanation on this page stay free permanently. Three more PDFs exist for this topic — the worked answer key, a harder problem set, and the answer key to that. They come with the University Introductory Statistics Solutions Bundle, beside the unit notes and the unit test, which is what keeps the rest of the series free.
What else exists for Discrete Random Variables
Three PDFs · 13 pages · all three are in the bundle below.
- Answer key — 3 pages. All 11 questions worked step by step, including the restrictions and the justifications. Not a list of final answers.
- Challenge problems — 7 pages, 7 problems. A separate sheet at exam-plus difficulty covering the same 6 concepts. Harder than anything on the free sheet.
- Challenge answer key — 3 pages. Every challenge problem worked to the same standard, with the checks shown.
- PDF, letter size, print-ready.
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Common questions
Is this worksheet really free?
Yes — the questions are on this page to read, and the PDF downloads directly, no email and no account. The one paid item is optional: the complete University Introductory Statistics Solutions Bundle, which covers every set at this level.
Which university courses is this for?
The course codes listed on this page are taken from the public course calendars of universities that teach a first, service-level statistics course. Each course orders and weights the chapters its own way, and some reach a chapter later or not at all — so check the outline for your own section to see where this set falls in your term.
What do I need to know before starting this set?
Secondary 5 mathematics, the mean and standard deviation from Descriptive Statistics, and independence, the multiplication rule and combinations from Probability Rules and Conditional Probability. No calculus: nothing here is differentiated or integrated.
How do I know whether a situation is binomial?
Four conditions: a number of trials fixed in advance, two outcomes per trial, the same probability of success on every trial, and independence. Run them over the wording one at a time. A rule that stops when something finally happens breaks the first; sampling without replacement from a small pool breaks the last two.
May I use the table instead of the binomial formula?
When a cumulative table for that n and p is printed, yes — and it is expected, because the alternative is a column of terms. Show the rewriting that turns the question into differences of P(X ≤ k) values, since that line is what earns the marks. Use the formula when the table does not cover your n and p, or when only one term is needed.
Why does the variance shortcut give the same answer as the definition?
Expanding (X − μ)² gives X² − 2μX + μ², and taking expectations term by term leaves E[X²] − μ², because E[X] is μ and μ is a constant. The shortcut is the definition after that expansion, so the two must agree — which is what makes computing both a genuine check.
What is the difference between the binomial and the Poisson model?
The binomial counts successes out of a fixed number of trials, so it has two parameters and a largest possible value. The Poisson counts events in an interval with no natural number of trials, so it has one parameter, no upper limit, and a variance equal to its mean.
Where is the normal approximation to the binomial?
In the next set, Continuous Distributions and the Normal Model, together with the size condition that says when it is allowed and the continuity correction that makes it accurate. Everything here is exact: the formula, or the cumulative table.
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